1948 U.S. National Championships – Women's Singles
| Women's Singles | |
|---|---|
| 1948 U.S. National Championships | |
| Champion |
|
| Runner-up |
|
| Final score | 4–6, 6–4, 15–13 |
Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the Women's Singles tennis title at the 1948 U.S. National Championships.[1][2]
Seeds
The seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.[3]
Louise Brough (Finalist)
Doris Hart (Quarterfinalist)
Margaret Osborne duPont (Champion)
Pat Canning Todd (Semifinalist)
Shirley Fry (Third round)
Beverly Baker (Quarterfinalist)
Gussy Moran (Semifinalist)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- r. = retired
Final Eight
| Quarterfinals | Semifinals | Finals | |||||||||||||||||
| 7 | |
6 | 6 | ||||||||||||||||
| 2 | |
4 | 4 | ||||||||||||||||
| 7 | |
8 | 4 | ||||||||||||||||
| 3 | |
10 | 6 | ||||||||||||||||
| 3 | |
1 | 6 | 6 | |||||||||||||||
| |
6 | 2 | 0 | ||||||||||||||||
| 3 | |
4 | 6 | 15 | |||||||||||||||
| 1 | |
6 | 4 | 13 | |||||||||||||||
| 1 | |
6 | 6 | ||||||||||||||||
| |
3 | 2 | |||||||||||||||||
| 1 | |
6 | 6 | ||||||||||||||||
| 4 | |
3 | 3 | ||||||||||||||||
| 4 | |
6 | 6 | ||||||||||||||||
| |
3 | 1 | |||||||||||||||||
References
- 1 2 Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
- ↑ "Exciting Game for Tennis Title.". Cairns Post (Qld. : 1909 - 1954) (Qld.: National Library of Australia). 21 September 1948. p. 1.
- ↑ G.P. Hughes, ed. (1949). Dunlop Lawn Tennis Annual and Almanack 1949. London: Ed. J. Burrow & Co. Ltd. pp. 159–164.
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