1990 FIFA World Cup qualification (CONMEBOL)

The South American (CONMEBOL) zone of qualification for the 1990 FIFA World Cup saw 9 teams competing for 2 direct places at the finals, with one extra place potentially on offer to the winner of a play-off. CONMEBOL member Argentina qualified automatically as reigning World Cup champions.

Format

Teams were divided into 3 groups of 3 teams each. The teams would play against each other on a home-and-away basis. The 2 group winners with the best record would qualify. The group winner with the worst record would advance to the CONMEBOL / OFC Intercontinental Play-off.

Draw

The draw for the qualifying groups took place in Zürich, Switzerland on 12 December 1987. During the draw teams were drawn from 3 seeded pots into the 3 qualifying groups.

Pot A Pot B Pot C

 Brazil
 Paraguay
 Uruguay

 Chile
 Colombia
 Peru

 Bolivia
 Ecuador
 Venezuela

Group 1

Pld W D L GF GA GD Pts
 Uruguay 430172+56
 Bolivia 430165+16
 Peru 40042860
  Bolivia Peru Uruguay
 BOL 2–1 2–1
 PER 1–2 0–2
 URU 2–0 2–0

Uruguay qualified with the second-best record among the group winners.

Group 2

Pld W D L GF GA GD Pts
 Colombia 421153+25
 Paraguay 42026714
 Ecuador 41124513
  Colombia Ecuador Paraguay
 COL 2–0 2–1
 ECU 0–0 3–1
 PAR 2–1 2–1

Colombia advanced to the CONMEBOL / OFC Intercontinental Play-off with the worst record among the group winners.

Group 3

Pld W D L GF GA GD Pts
 Brazil 4310131+127
 Chile 421194+55
 Venezuela 4004118170
  Brazil Chile Venezuela
 BRA 2–0 6–0
 CHI 1–1 5–0
 VEN 0–4 1–3

Brazil qualified with the best record among the group winners.

Notes

    External links

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