1998 CONCACAF Women's Championship
1998 CONCACAF Women's Championship| 1998 Coupe d'Or CONCACAF Femmes |
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| Tournament details |
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| Host country |
Canada |
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| Dates |
19 July - 19 December 1998 |
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| Teams |
10 (from 1 confederation) |
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| Final positions |
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| Champions |
 Canada (1st title) |
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| Runners-up |
 Mexico |
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| Third place |
 Costa Rica |
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| Fourth place |
 Guatemala |
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| Tournament statistics |
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| Best player |
Silvana Burtini[1] |
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The 1998 CONCACAF Women's Championship determined CONCACAF's qualifiers for the FIFA Women's World Cup 1999. The final stage of the tournament took place at Etobicoke and Scarborough in Toronto, Canada. Canada took the sole automatic qualifying place by finishing first. The runner-up, Mexico, qualified after defeating Argentina in a two-leg playoff in December 1998.
This event was the fourth and final staging of CONCACAF's Women's Championship under that name. It would be renamed the CONCACAF Women's Gold Cup in 2000.
This was the only edition of CONCACAF's Women's Championship or the CONCACAF Women's Gold Cup in which the traditional superpower of CONCACAF women's football (soccer), the USA, did not participate. The US team directly qualified for the 1999 Women's World Cup as hosts of the event.
UNCAF/CFU Qualifying Tournament
Group A
Group B
Third place play-off
Final
CFU Qualifying Round
Guatemala, Haiti, Costa Rica and Trinidad and Tobago qualified for the final tournament.
Final tournament
Group A
Group B
Knockout stage
Semi-finals
Third place playoff
Final
Awards
| 1998 CONCACAF's Women's Championship Winners |
Canada
First title |
References
External links
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| | Championship era | |
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| | Gold Cup era | |
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| | Championship era | |
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| | Squads | |
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Haiti
El Salvador
Honduras
Martinique
Puerto Rico
Trinidad and Tobago