American Airlines Flight 63 (Flagship Ohio)

For other incidents on board flights designated American Airlines Flight 63, see American Airlines Flight 63 (disambiguation).
American Airlines Flight 63

An American Airlines DC-3 similar to Flagship Ohio.
Accident summary
Date 28 July 1943
Summary Loss of control due to severe turbulence and violent downdrafts
Site Allen County, 1.6 kilometres (0.99 mi) west of Trammel, Kentucky
Passengers 18
Crew 4
Fatalities 20
Survivors 2
Aircraft type Douglas DC-3-178
Aircraft name Flagship Ohio
Operator American Airlines
Registration NC16014
Flight origin Cleveland, Ohio
1st stopover Columbus, Ohio
2nd stopover Dayton, Ohio
3rd stopover Cincinnati, Ohio
4th stopover Louisville, Kentucky
Last stopover Nashville, Tennessee
Destination Memphis, Tennessee

On 28 July 1943 American Airlines Flight 63 was flown by a Douglas DC-3, named Flagship Ohio, routing Cleveland-Columbus-Dayton-Cincinnati-Louisville-Nashville-Memphis, that crashed on the Louisville-Nashville sector about 1.6 miles (2.6 km) west of Trammel, Kentucky. The aircraft descended from 200 feet (61 m) until it struck trees, then slid across an open field and stopped in an upright position.[1] Of the 22 people on board, 20 died. The cause of the crash was loss of control due to severe turbulence and violent downdrafts.

Aircraft

Flagship Ohio was a Douglas DC-3 manufactured by the Douglas Aircraft Company and owned and operated by American Airlines. Since its first flight in 1936, the aircraft had logged 17,991 hours of flight time.[1] At the time of the crash, it serviced a domestic scheduled passenger route with several stops in Ohio, Kentucky, and Tennessee.

Crash

Flight 63 departed Cleveland at approximately 5:42 pm on 28 July 1943. The flight proceeded normally during its scheduled stops in Columbus, Dayton, Cincinnati, and Louisville. The aircraft arrived at its fourth stop, Louisville, at 9:42 pm. After refueling, the flight received clearance to depart at 9:54 pm.[1] During the Louisville-Nashville leg, the Flagship Ohio was crewed by four American Airlines personnel, and carried eighteen passengers.

The aircraft's departure clearance specified an altitude of 2,500 feet (760 m) to Smiths Grove, Kentucky, and then at 2,000 feet (610 m) onward to Nashville.[1] The projected arrival time was 10:54 pm — an hour's flight.

Thunderstorms around Smiths Grove caused extreme turbulence and strong downdrafts which forced the plane to lose altitude. The Smiths Grove area is characterized by hilly terrain with an altitude that ranges from 695 to 720 ft (212 to 219 m) above sea level.[1] The plane clipped a clump of trees before skidding across an open field until it came to rest in an upright position in a copse of trees approximately 1,000 feet (300 m) away from its initial point of impact.[1]

The Civil Aeronautics Board investigated the crash and determined that the extreme turbulence and conditions caused by the nearby thunderstorm created such severe flying conditions that the pilot was unable to maintain control of the aircraft.

Loss of control of the aircraft due to unusually severe turbulence and violent downdraft caused by a thunderstorm of unknown and unpredictable intensity.
— Civil Aeronautics Board, CAB File No. 325-43

All four crewmembers died in the crash. Of the eighteen passengers, only two survived.[1]

After the loss of the Flagship Ohio, American Airlines replaced the aircraft on the Cleveland-Columbus-Dayton-Cincinnati-Louisville-Nashville-Memphis route with sister DC-3 Flagship Missouri. Three months later, on 15 October 1943, Flagship Missouri crashed on the Nashville-Memphis leg of the flight.

See also

References

  1. 1 2 3 4 5 6 7 Accident description for American Airlines Flight 63 at the Aviation Safety Network. Retrieved on 2009-05-24.

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