Fleischner's theorem

A 2-vertex-connected graph, its square, and a Hamiltonian cycle in the square

In graph theory, a branch of mathematics, Fleischner's theorem gives a sufficient condition for a graph to contain a Hamiltonian cycle. It states that, if G is a 2-vertex-connected graph, then the square of G is Hamiltonian. it is named after Herbert Fleischner, who published its proof in 1974.

Definitions and statement

An undirected graph G is Hamiltonian if it contains a cycle that touches each of its vertices exactly once. It is 2-vertex-connected if it does not have an articulation vertex, a vertex whose deletion would leave the remaining graph disconnected. Not every 2-vertex-connected graph is Hamiltonian; counterexamples include the Petersen graph and the complete bipartite graph K2,3.

The square of G is a graph G2 that has the same vertex set as G, and in which two vertices are adjacent if and only if they have distance at most two in G. Fleischner's theorem states that the square of a finite 2-vertex-connected graph with at least three vertices must always be Hamiltonian. Equivalently, the vertices of every 2-vertex-connected graph G may be arranged into a cyclic order such that adjacent vertices in this order are at distance at most two from each other in G.

Extensions

In Fleischner's theorem, it is possible to constraint the Hamiltonian cycle so that it includes three designated edges passing through two chosen vertices.[1]

In addition to having a Hamiltonian cycle, the square of a 2-vertex-connected graph G must also be Hamiltonian connected (meaning that it has a Hamiltonian path starting and ending at any two designated vertices) and 1-Hamiltonian (meaning that if any vertex is deleted, the remaining graph still has a Hamiltonian cycle).[2] It must also be vertex pancyclic, meaning that for every vertex v and every integer k with 3  k  |V(G)|, there exists a cycle of length k containing v.[3]

If a graph G is not 2-vertex-connected, then its square may or may not have a Hamiltonian cycle, and determining whether it does have one is NP-complete.[4]

An infinite graph cannot have a Hamiltonian cycle, because every cycle is finite, but Carsten Thomassen proved that if G is an infinite locally finite 2-vertex-connected graph with a single end then G2 necessarily has a doubly infinite Hamiltonian path.[5] More generally, if G is locally finite, 2-vertex-connected, and has any number of ends, then G2 has a Hamiltonian circle. In a compact topological space formed by viewing the graph as a simplicial complex and adding an extra point at infinity to each of its ends, a Hamiltonian circle is defined to be a subspace that is homeomorphic to a Euclidean circle and covers every vertex.[6]

History

A proof of Fleischner's theorem was announced by Herbert Fleischner in 1971 and published by him in 1974, solving a 1966 conjecture of Crispin Nash-Williams also made independently by L. W. Beineke and Michael D. Plummer.[7] In his review of Fleischner's paper, Nash-Williams wrote that it had solved "a well known problem which has for several years defeated the ingenuity of other graph-theorists".[8]

Fleischner's original proof was complicated. Václav Chvátal, in the work in which he invented graph toughness, observed that the square of a k-vertex-connected graph is necessarily k-tough; he conjectured that 2-tough graphs are Hamiltonian, from which another proof of Fleischner's theorem would have followed.[9] Counterexamples to this conjecture were later discovered,[10] but the possibility that a finite bound on toughness might imply Hamiltonicity remains an important open problem in graph theory. A simpler proof both of Fleischner's theorem, and of its extensions by Chartrand et al. (1974), was given by Říha (1991),[11] and another simplified proof of the theorem was given by Georgakopoulos (2009a).[12]

References

Notes

Primary sources

Secondary sources

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