Irregularity of distributions

The irregularity of distributions problem, stated first by Hugo Steinhaus, is a numerical problem with a surprising result. The problem is to find N numbers, x_1,\ldots,x_N, all between 0 and 1, for which the following conditions hold:

Mathematically, we are looking for a sequence of real numbers

x_1,\ldots,x_N

such that for every n  {1, ..., N} and every k  {1, ..., n} there is some i  {1, ..., n} such that

\frac{k-1}{n} \leq x_i < \frac{k}{n}.

Solution

The surprising result is that there is a solution up to N = 17, but starting at N = 18 and above it is impossible. A possible solution for N  17 is shown diagrammatically on the right; numerically it is as follows:

A possible solution for N = 17 shown diagrammatically. In each row n, there are n “vines” which are all in different nths. For example, looking at row 5, it can be seen that 0 < x1 < 1/5 < x5 < 2/5 < x3 < 3/5 < x4 < 4/5 < x2 < 1. The numerical values are printed in the article text.

\begin{align}
x_{1} & = 0.029 \\
x_{2} & = 0.971 \\
x_{3} & = 0.423 \\
x_{4} & = 0.71 \\
x_{5} & = 0.27 \\
x_{6} & = 0.542 \\
x_{7} & = 0.852 \\
x_{8} & = 0.172 \\
x_{9} & = 0.62 \\
x_{10} & = 0.355 \\
x_{11} & = 0.774 \\
x_{12} & = 0.114 \\
x_{13} & = 0.485 \\
x_{14} & = 0.926 \\
x_{15} & = 0.207 \\
x_{16} & = 0.677 \\
x_{17} & = 0.297
\end{align}

In this example, considering for instance the first 5 numbers, we have

0 < x_1 < \frac{1}{5} < x_5 < \frac{2}{5} < x_3 < \frac{3}{5} < x_4 < \frac{4}{5} < x_2 < 1.

References

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