Limpet Island
  Location in Antarctica | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 67°38′S 68°18′W / 67.633°S 68.300°WCoordinates: 67°38′S 68°18′W / 67.633°S 68.300°W |
| Country | |
|
None | |
| Demographics | |
| Population | Uninhabited |
| Additional information | |
| Administered under the Antarctic Treaty System | |
Limpet Island is the southernmost of the Léonie Islands, Antarctica, lying in the entrance to Ryder Bay, close off the southeast coast of Adelaide Island. The Léonie Islands were discovered and first roughly surveyed in 1909 by the Fourth French Antarctic Expedition under Jean-Baptiste Charcot. Limpet Island was surveyed in 1948 by the Falkland Islands Dependencies Survey and so named by them because of the large number of limpet shells found there.[1]
See also
References
- ↑ "Limpet Island". Geographic Names Information System. United States Geological Survey. Retrieved 2013-06-15.
This article incorporates public domain material from the United States Geological Survey document "Limpet Island" (content from the Geographic Names Information System).
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