Markov–Kakutani fixed-point theorem

In mathematics, the Markov–Kakutani fixed-point theorem, named after Andrey Markov and Shizuo Kakutani, states that a commuting family of continuous affine self-mappings of a compact convex subset in a locally convex topological vector space has a common fixed point.

Statement

Let E be a locally convex topological vector space. Let C be a compact convex subset of E. Let S be a commuting family of self-mappings T of C which are continuous and affine, i.e. T(tx +(1  t)y) = tT(x) + (1  t)T(y) for t in [0,1] and x, y in C. Then the mappings have a common fixed point in C.

Proof for a single affine self-mapping

Let T be a continuous affine self-mapping of C.

For x in C define other elements of C by

 x(N)={1\over N+1}\sum_{n=0}^N T^n(x).

Since C is compact, there is a convergent subnet in C:

 x(N_i)\rightarrow y. \,

To prove that y is a fixed point, it suffices to show that f(Ty) = f(y) for every f in the dual of E. Since C is compact, |f| is bounded on C by a positive constant M. On the other hand

 |f(Tx(N))-f(x(N))|={1\over N+1} |f(T^{N+1}x)-f(x)|\le {2M\over N+1}.

Taking N = Ni and passing to the limit as i goes to infinity, it follows that

 f(Ty) = f(y). \,

Hence

Ty = y. \,

Proof of theorem

The set of fixed points of a single affine mapping T is a non-empty compact convex set CT by the result for a single mapping. The other mappings in the family S commute with T so leave CT invariant. Applying the result for a single mapping successively, it follows that any finite subset of S has a non-empty fixed point set given as the intersection of the compact convex sets CT as T ranges over the subset. From the compactness of C it follows that the set

 C^S=\{y\in C|Ty=y, \, T\in S\}=\bigcap_{T\in S} C^T \,

is non-empty (and compact and convex).

References

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