q-exponential
In combinatorial mathematics, a q-exponential is a q-analog of the exponential function,
namely the eigenfunction of a q-derivative. There are many q-derivatives, for example, the classical q-derivative, the Askey-Wilson operator, etc. Therefore, unlike the classical exponentials, q-exponentials are not unique. For example,
is the q-exponential corresponding to the classical q-derivative while
are eigenfunctions of the Askey-Wilson operators.
Definition
The q-exponential
is defined as
where
is the q-factorial and
is the q-Pochhammer symbol. That this is the q-analog of the exponential follows from the property
where the derivative on the left is the q-derivative. The above is easily verified by considering the q-derivative of the monomial
Here,
is the q-bracket.
Properties
For real
, the function
is an entire function of z. For
,
is regular in the disk
.
Note the inverse,
.
Relations
For
, a function that is closely related is
It is a special case of the basic hypergeometric series,
Clearly,
References
- Exton, H. (1983), q-Hypergeometric Functions and Applications, New York: Halstead Press, Chichester: Ellis Horwood, ISBN 0853124914, ISBN 0470274530, ISBN 978-0470274538
- Gasper, G. & Rahman, M. (2004), Basic Hypergeometric Series, Cambridge University Press, ISBN 0521833574
- Ismail, M. E. H. (2005), Classical and Quantum Orthogonal Polynomials in One Variable, Cambridge University Press.
- Jackson, F. H. (1908), "On q-functions and a certain difference operator", Transactions of the Royal Society of Edinburgh, 46, 253-281.
![e_q(z)=
\sum_{n=0}^\infty \frac{z^n}{[n]_q!} =
\sum_{n=0}^\infty \frac{z^n (1-q)^n}{(q;q)_n} =
\sum_{n=0}^\infty z^n\frac{(1-q)^n}{(1-q^n)(1-q^{n-1}) \cdots (1-q)}](../I/m/e15c462a0b44434270ccf2f394fb799d.png)


![\left(\frac{d}{dz}\right)_q z^n = z^{n-1} \frac{1-q^n}{1-q}
=[n]_q z^{n-1}.](../I/m/23a1aaaf482ca1996693456a7858adec.png)

