Trigamma function

, in a rectangular region of the complex plane. It is generated using Domain coloring method.In mathematics, the trigamma function, denoted
, is the second of the polygamma functions, and is defined by
-
.
It follows from this definition that
where
is the digamma function. It may also be defined as the sum of the series
making it a special case of the Hurwitz zeta function
Note that the last two formulæ are valid when
is not a natural number.
Calculation
A double integral representation, as an alternative to the ones given above, may be derived from the series representation:
using the formula for the sum of a geometric series. Integration by parts yields:
An asymptotic expansion as a Laurent series is
if we have chosen
, i.e. the Bernoulli numbers of the second kind.
Recurrence and reflection formulae
The trigamma function satisfies the recurrence relation
and the reflection formula
which immediately gives the value for z=1/2.
Special values
The trigamma function has the following special values:
where K represents Catalan's constant.
There are no roots on the real axis of
, but there exist infinitely many pairs of roots
for
. Each such pair of root approach
quickly and their imaginary part increases slowly logarithmic with n.
E.g.
and
are the first two roots with
.
Appearance
The trigamma function appears in the next surprising sum formula:[1]
See also
Notes
- ↑ Mező, István (2013). "Some infinite sums arising from the Weierstrass Product Theorem". Applied Mathematics and Computation 219: 9838–9846. doi:10.1016/j.amc.2013.03.122.
References
- Milton Abramowitz and Irene A. Stegun, Handbook of Mathematical Functions, (1964) Dover Publications, New York. ISBN 0-486-61272-4. See section §6.4
- Eric W. Weisstein. Trigamma Function -- from MathWorld--A Wolfram Web Resource













![\sum_{n=1}^\infty\frac{n^2-\frac12}{\left(n^2+\frac12\right)^2}\left[\psi_1\left(n-\frac{i}{\sqrt{2}}\right)+\psi_1\left(n+\frac{i}{\sqrt{2}}\right)\right]=
-1+\frac{\sqrt{2}}{4}\pi\coth\left(\frac{\pi}{\sqrt{2}}\right)-\frac{3\pi^2}{4\sinh^2\left(\frac{\pi}{\sqrt{2}}\right)}+\frac{\pi^4}{12\sinh^4\left(\frac{\pi}{\sqrt{2}}\right)}\left(5+\cosh\left(\pi\sqrt{2}\right)\right).](../I/m/889b5db8a4801f746b93470924df08e4.png)