Weierstrass product inequality

In mathematics, the Weierstrass product inequality states that given real numbers 0 ≤ a, b, c, d ≤ 1, it follows that

(1-a)(1-b)(1-c)(1-d)+a+b+c+d \geq 1. \,

The inequality is named after the German mathematician Karl Weierstrass.

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