1925 Paris–Roubaix
| Race details | |||
|---|---|---|---|
| Date | 12 April | ||
| Distance | 260 km (161.6 mi) | ||
| Winning time | 9h 16' 32" (28.030 km/h or 17.417 mph) | ||
| Palmares | |||
| Winner | |||
| Second | |||
| Third | |||
The 1925 Paris–Roubaix was the 26th edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 12 April 1925 and stretched 260 km (162 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Félix Sellier from Belgium.[2]
Results
| Rank | Cyclist | Time |
|---|---|---|
| 1 | |
9h 16' 32″ |
| 2 | |
+0' 00″ |
| 3 | |
+0' 00″ |
| 4 | |
+0' 00″ |
| 5 | |
+0' 00″ |
| 6 | |
+0' 00″ |
References
- ↑ "26th Paris – Roubaix, 1925". bikeraceinfo. Retrieved 2 April 2015.
- 1 2 "1925 » 26th Paris – Roubaix". ProCyclingStats. Retrieved 2 April 2015.
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