1998 Boston Cup – Doubles

Doubles
1998 Boston Cup
Champions	Lisa Raymond Rennae Stubbs
Runners-up	Mariaan de Swardt Mary Joe Fernández
Final score	6–4, 6–4

Lisa Raymond and Rennae Stubbs won in the final 6–4, 6–4 against Mariaan de Swardt and Mary Joe Fernández.

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

1. Lisa Raymond / Rennae Stubbs (Champions)
2. Naoko Kijimuta / Nana Miyagi (First Round)
3. Kristine Kunce / Corina Morariu (First Round)
4. Amanda Coetzer / Barbara Schett (First Round)

Draw

Key

Q = Qualifier WC = Wild Card LL = Lucky Loser

Alt = Alternate SE = Special Exempt PR = Protected Ranking

w/o = Walkover r = Retired d = Defaulted

	First Round							Quarterfinals							Semifinals							Final
	1	L Raymond R Stubbs	6	6
		E de Lone S-T Wang	3	1				1	L Raymond R Stubbs	6	6
		N de Villiers L McShea	6	1	4				S Farina A Huber	4	3
		S Farina A Huber	1	6	6										1	L Raymond R Stubbs	7	6
	3	K Kunce C Morariu	2	2											Q	C Black I Selyutina	6	1
	Q	C Black I Selyutina	6	6				Q	C Black I Selyutina	6	4	6
		A Ellwood T Musgrave	w/o						A Ellwood T Musgrave	2	6	2
		O Barabanschikova E Likhovtseva																				1	Lisa Raymond Rennae Stubbs	6	6
		L Horn M Paz	4	3																			Mariaan de Swardt Mary Joe Fernández	4	4
		R McQuillan N Pratt	6	6					R McQuillan N Pratt	3	3
		C Cristea R Dragomir	1	7	6				C Cristea R Dragomir	6	6
	4	A Coetzer B Schett	6	6	2											C Cristea R Dragomir	3	7	4
		K Freye Y Yoshida	6	6												M de Swardt M J Fernández	6	5	6
	WC	S Kleinová B Rippner	2	1					K Freye Y Yoshida	3	3
		M de Swardt M J Fernández	6	7					M de Swardt M J Fernández	6	6
	2	N Kijimuta N Miyagi	1	6

External links

• 1998 Boston Cup Doubles Draw