2013 ATP World Tour Finals – Doubles
Marcel Granollers and Marc López were the defending champions, but were knocked out in the round robin stage.
David Marrero and Fernando Verdasco won the title, defeating Bob and Mike Bryan in the final, 7–5, 6–7(3–7), [10–7].
Seeds
Draw
Key
Finals
Group A
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Bryan
Bryan |
Dodig
Melo |
Qureshi
Rojer |
Fyrstenberg
Matkowski |
RR W–L |
Set W–L |
Game W–L |
Standings |
1 |
Bob Bryan
Mike Bryan |
|
6–3, 3–6, [8–10] |
7–6(7–3), 1–6, [14–12] |
4–6, 6–3, [10–5] |
2–1 |
5–4 (55.6%) |
29–31 (48.3%) |
2 |
3 |
Ivan Dodig
Marcelo Melo |
3–6, 6–3, [10–8] |
|
7–5, 3–6, [11–9] |
6–3, 3–6, [10–2] |
3–0 |
6–3 (66.7%) |
31–29 (51.7%) |
1 |
5 |
Aisam-ul-Haq Qureshi
Jean-Julien Rojer |
6–7(3–7), 6–1, [12–14] |
5–7, 6–3, [9–11] |
|
3–6, 6–7(8–10) |
0–3 |
2–6 (25.0%) |
32–33 (49.2%) |
4 |
8 |
Mariusz Fyrstenberg
Marcin Matkowski |
6–4, 3–6, [5–10] |
3–6, 6–3, [2–10] |
6–3, 7–6(10–8) |
|
1–2 |
4–4 (50.0%) |
31–30 (50.8%) |
3 |
Standings are determined by: 1) Number of wins; 2) Number of matches; 3) In two-players-ties, head-to-head records; 4) In three-players-ties, percentage of sets won, or of games won; 5) Steering Committee decision.
Group B
|
|
Peya
Soares |
Granollers
López |
Marrero
Verdasco |
Paes
Štěpánek |
RR W–L |
Set W–L |
Game W–L |
Standings |
2 |
Alexander Peya
Bruno Soares |
|
3–6, 6–4, [10–5] |
6–3, 7–5 |
3–6, 7–5, [8–10] |
2–1 |
5–3 (62.5%) |
33–30 (52.4%) |
1 |
4 |
Marcel Granollers
Marc López |
6–3, 4–6, [5–10] |
|
1–6, 4–6 |
4–6, 7–6(7–5), [10–8] |
1–2 |
3–5 (37.5%) |
27–34 (44.3%) |
3 |
6 |
David Marrero
Fernando Verdasco |
3–6, 5–7 |
6–1, 6–4 |
|
6–4, 7–6(7–5) |
2–1 |
4–2 (66.7%) |
33–28 (54.1%) |
2 |
7 |
Leander Paes
Radek Štěpánek |
6–3, 5–7, [10–8] |
6–4, 6–7(5–7), [8–10] |
4–6, 6–7(5–7) |
|
1–2 |
3–5 (37.5%) |
34–35 (49.3%) |
4 |
Standings are determined by: 1) Number of wins; 2) Number of matches; 3) In two-players-ties, head-to-head records; 4) In three-players-ties, percentage of sets won, or of games won; 5) Steering Committee decision.
References
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