Alma Township, Harlan County, Nebraska
| Alma Township | |
|---|---|
| Township | |
 Location in Harlan County | |
| Coordinates: 40°07′32″N 099°20′44″W / 40.12556°N 99.34556°WCoordinates: 40°07′32″N 099°20′44″W / 40.12556°N 99.34556°W | |
| Country | United States |
| State | Nebraska |
| County | Harlan |
| Area | |
| • Total | 35.16 sq mi (91.06 km2) |
| • Land | 34.17 sq mi (88.51 km2) |
| • Water | 0.98 sq mi (2.55 km2) 2.8% |
| Elevation | 2,090 ft (637 m) |
| Population (2000) | |
| • Total | 213 |
| • Density | 6.2/sq mi (2.4/km2) |
| GNIS feature ID | 0837850 |
Alma Township is one of sixteen townships in Harlan County, Nebraska, United States. The population was 213 at the 2000 census. A 2006 estimate placed the township's population at 195.[1]
See also
References
- ↑ "Subcounty population estimates: Nebraska 2000-2006" (CSV). United States Census Bureau, Population Division. 2007-06-28. Archived from the original on 18 February 2008. Retrieved 2008-02-26.
External links
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