Delaware Township, Ripley County, Indiana

Delaware Township
Township
Coordinates: 39°10′50″N 85°14′52″W / 39.18056°N 85.24778°W / 39.18056; -85.24778Coordinates: 39°10′50″N 85°14′52″W / 39.18056°N 85.24778°W / 39.18056; -85.24778
Country United States
State Indiana
County Ripley
Government
  Type Indiana township
Area
  Total 33.27 sq mi (86.2 km2)
  Land 33.21 sq mi (86.0 km2)
  Water 0.06 sq mi (0.2 km2)
Elevation[1] 928 ft (283 m)
Population (2010)
  Total 1,437
  Density 43.3/sq mi (16.7/km2)
FIPS code 18-17524[2]
GNIS feature ID 453262

Delaware Township is one of eleven townships in Ripley County, Indiana. As of the 2010 census, its population was 1,437 and it contained 578 housing units.[3]

Geography

According to the 2010 census, the township has a total area of 33.27 square miles (86.2 km2), of which 33.21 square miles (86.0 km2) (or 99.82%) is land and 0.06 square miles (0.16 km2) (or 0.18%) is water.[3]

References

  1. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
  3. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.

External links


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