Doomsday rule

John Conway, inventor of the Doomsday algorithm.

The Doomsday rule or Doomsday algorithm is a way of calculating the day of the week of a given date. It provides a perpetual calendar because the Gregorian calendar moves in cycles of 400 years.

This algorithm for mental calculation was devised by John Conway^[1]^[2] after drawing inspiration from Lewis Carroll's work on a perpetual calendar algorithm.^[3]^[4] It takes advantage of each year having a certain day of the week (the doomsday) upon which certain easy-to-remember dates fall; for example, 4/4, 6/6, 8/8, 10/10, 12/12, and the last day of February all occur on the same day of the week in any given year. Applying the Doomsday algorithm involves three steps:

Determine the "anchor day" for the century.
Use the anchor day for the century to calculate the doomsday for the year.
Choose the closest date out of the ones that always fall on the doomsday (e.g. 4/4, 6/6, 8/8), and count the number of days (modulo 7) between that date and the date in question to arrive at the day of the week.

This technique applies to both the Gregorian calendar A.D. and the Julian calendar, although their doomsdays will usually be different days of the week.

Since this algorithm involves treating days of the week like numbers modulo 7, John Conway suggests thinking of the days of the week as "Noneday" or "Sansday" (for Sunday), "Oneday", "Twosday", "Treblesday", "Foursday", "Fiveday", and "Six-a-day". There are some languages, like Portuguese and Galician who base some of the names of the week days in their positional order.

The algorithm is simple enough for anyone with basic arithmetic ability to do the calculations mentally. Conway can usually give the correct answer in under two seconds. To improve his speed, he practices his calendrical calculations on his computer, which is programmed to quiz him with random dates every time he logs on.^[5]

Doomsdays for some contemporary years

Doomsday for the current year in the Gregorian calendar (2016) is Monday.

For some other contemporary years :

**Doomsdays for the Gregorian calendar**
Mon.	Tue.	Wed.	Thu.	Fri.	Sat.	Sun.	Mon.	Tue.	Wed.	Thu.	Fri.	Sat.	Sun.
1898	1899	1900	1901	1902	1903	→	1904	1905	1906	1907	→	1908	1909
1910	1911	→	1912	1913	1914	1915	→	1916	1917	1918	1919	→	1920
1921	1922	1923	→	1924	1925	1926	1927	→	1928	1929	1930	1931	→
1932	1933	1934	1935	→	1936	1937	1938	1939	→	1940	1941	1942	1943
→	1944	1945	1946	1947	→	1948	1949	1950	1951	→	1952	1953	1954
1955	→	1956	1957	1958	1959	→	1960	1961	1962	1963	→	1964	1965
1966	1967	→	1968	1969	1970	1971	→	1972	1973	1974	1975	→	1976
1977	1978	1979	→	1980	1981	1982	1983	→	1984	1985	1986	1987	→
1988	1989	1990	1991	→	1992	1993	1994	1995	→	1996	1997	1998	1999
→	2000	2001	2002	2003	→	2004	2005	2006	2007	→	2008	2009	2010
2011	→	2012	2013	2014	2015	→	2016	2017	2018	2019	→	2020	2021
2022	2023	→	2024	2025	2026	2027	→	2028	2029	2030	2031	→	2032
2033	2034	2035	→	2036	2037	2038	2039	→	2040	2041	2042	2043	→
2044	2045	2046	2047	→	2048	2049	2050	2051	→	2052	2053	2054	2055
→	2056	2057	2058	2059	→	2060	2061	2062	2063	→	2064	2065	2066
2067	→	2068	2069	2070	2071	→	2072	2073	2074	2075	→	2076	2077
2078	2079	→	2080	2081	2082	2083	→	2084	2085	2086	2087	→	2088
2089	2090	2091	→	2092	2093	2094	2095	→	2096	2097	2098	2099	2100

Notes: Fill in the table horizontally, skipping one column for each leap year. This table cycles every 28 years, except in the Gregorian calendar on years multiple of 100 (like 1900 which is not a leap year) that are not multiple of 400 (like 2000 which is still a leap year). The full cycle is 28 years (1,461 weeks) in the Julian calendar, 400 years (20,871 weeks) in the Gregorian calendar.

Memorable dates that always land on Doomsday

One can easily find the day of the week of a given calendar date by using a nearby Doomsday as a reference point. To help with this, the following is a list of easy-to-remember dates for each month that always land on the Doomsday.

As mentioned above, the last day of February defines the doomsday. For January, January 3 is a doomsday during common years and January 4 a doomsday during leap years, which can be remembered as "the 3rd during 3 years in 4, and the 4th in the 4th year". For March, one can remember the pseudo-date "March 0", which refers to the day before March 1, i.e. the last day of February.

For the months April through December, the even numbered months are covered by the double dates 4/4, 6/6, 8/8, 10/10, and 12/12, all of which fall on the doomsday. The odd numbered months can be remembered with the mnemonic "I work from 9 to 5 at the 7–11", i.e., 9/5, 7/11, and also 5/9 and 11/7, are all doomsdays.

Month	Memorable date	Month/Day	Mnemonic^[6]
January	January 3 (common years), January 4 (leap years)	1/3 or 1/4	the 3rd 3 years in 4 and the 4th in the 4th
February	February 28 (common years), February 29 (leap years)	2/28 or 2/29	last day of February
March	"March 0"	3/0	last day of February
April	April 4	4/4	4/4, 6/6, 8/8, 10/10, 12/12
May	May 9	5/9	9-to-5 at 7-11
June	June 6	6/6	4/4, 6/6, 8/8, 10/10, 12/12
July	July 11	7/11	9-to-5 at 7-11
August	August 8	8/8	4/4, 6/6, 8/8, 10/10, 12/12
September	September 5	9/5	9-to-5 at 7-11
October	October 10	10/10	4/4, 6/6, 8/8, 10/10, 12/12
November	November 7	11/7	9-to-5 at 7-11
December	December 12	12/12	4/4, 6/6, 8/8, 10/10, 12/12

Since the Doomsday for a particular year is directly related to weekdays of dates in the period from March through February of the next year, common years and leap years have to be distinguished for January and February of the same year.

Examples

To find which day of the week Christmas Day of 2006 was: in the year 2006, Doomsday was Tuesday. Since December 12 is a Doomsday, December 25, being thirteen days afterwards (two weeks less a day), fell on a Monday.

It is useful to note that Christmas Day is always the day before Doomsday ("One off Doomsday"). In addition, July 4 is always on a Doomsday, as is Halloween (October 31).

To find the day of week that the September 11, 2001 attacks on the World Trade Center occurred: the century anchor was Tuesday, and Doomsday for 2001 is one day beyond, which is Wednesday. September 5 was a Doomsday, and September 11, six days later, fell on a Tuesday.

Finding a year's Doomsday

We first take the anchor day for the century. For the purposes of the Doomsday rule, a century starts with '00 and ends with '99. The following table shows the anchor day of centuries 1800–1899, 1900–1999, 2000–2099 and 2100–2199.

Century	Anchor day	Mnemonic	Index (day of week)
1800–1899	Friday	—	5 (Fiveday)
1900–1999	Wednesday	We-in-dis-day (most living people were born in that century)	3 (Treblesday)
2000–2099	Tuesday	Y-Tue-K or Twos-day (Y2K was at the head of this century)	2 (Twosday)
2100–2199	Sunday	Twenty-one-day is Sunday (2100 is the start of the next century)	0 (Noneday)

Next, we find the year's Doomsday. To accomplish that according to Conway:

Divide the year's last two digits (call this $y$ ) by 12 and let $a$ be the floor of the quotient.
Let $b$ be the remainder of the same quotient.
Divide that remainder by 4 and let $c$ be the floor of the quotient.
Let $d$ be the sum of the three numbers ( $d = a + b + c$ ). (It is again possible here to divide by seven and take the remainder. This number is equivalent, as it must be, to the sum of the last two digits of the year taken collectively plus the floor of those collective digits divided by four.)
Count forward the specified number of days ( $d$ or the remainder of $d / 7$ ) from the anchor day to get the year's Doomsday.

\begin{matrix}\left({\left\lfloor{\frac{y}{12}}\right\rfloor+y \bmod 12+\left\lfloor{\frac{y \bmod 12}{4}}\right\rfloor}\right) \bmod 7+\rm{anchor}=\rm{Doomsday}\end{matrix}

For the twentieth-century year 1966, for example:

\begin{matrix}\left({\left\lfloor{\frac{66}{12}}\right\rfloor+66 \bmod 12+\left\lfloor{\frac{66 \bmod 12}{4}}\right\rfloor}\right) \bmod 7+\rm{Wednesday} & = & \left(5+6+1\right) \bmod 7+\rm{Wednesday} \\ \ & = & \rm{Monday}\end{matrix}

As described in bullet 4, above, this is equivalent to:

\begin{matrix}\left({66 + \left\lfloor{\frac{66}{4}}\right\rfloor}\right) \bmod 7+\rm{Wednesday} & = & \left(66+16\right) \bmod 7+\rm{Wednesday} \\ \ & = & \rm{Monday}\end{matrix}

So Doomsday in 1966 fell on Monday.

Similarly, Doomsday in 2005 is on a Monday:

\left({\left\lfloor{\frac{5}{12}}\right\rfloor+5 \bmod 12+\left\lfloor{\frac{5 \bmod 12}{4}}\right\rfloor}\right) \bmod 7+\rm{Tuesday}=\rm{Monday}

Why it works

Doomsday rule

The doomsday calculation is effectively calculating the number of days between any given date in the base year and the same date in the current year, then taking the remainder modulo 7. When both dates come after the leap day (if any), the difference is just $365 y + y / 4$ (rounded down). But 365 equals 52 × 7 + 1, so after taking the remainder we get just

\left(y + \left\lfloor \frac{y}{4} \right\rfloor\right) \bmod 7.

This gives a simpler formula if one is comfortable dividing large values of $y$ by both 4 and 7. For example, we can compute

\left(66 + \left\lfloor \frac{66}{4} \right\rfloor\right) \bmod 7 = (66 + 16) \bmod 7 = 82 \bmod 7 = 5

which gives the same answer as in the example above.

Where 12 comes in is that the pattern of $(y + ⌊ y / 4 ⌋) mod 7$ almost repeats every 12 years. After 12 years, we get $(12 + 12 / 4) mod 7 = 15 mod 7 = 1$ . If we replace $y$ by $y mod 12$ , we are throwing this extra day away; but adding back in $⌊ y / 12 ⌋$ compensates for this error, giving the final formula.

The "odd + 11" method

A simple flowchart showing the Odd+11 method.

A simpler method for finding the year's doomsday was discovered in 2010 by Chamberlain Fong and Michael K. Walters,^[7] and described in their paper submitted to the 7th International Congress on Industrial and Applied Mathematics (2011). Called the "odd + 11" method, it is equivalent^[7] to computing

\left(y + \left\lfloor \frac{y}{4} \right\rfloor\right) \bmod 7

It is well suited to mental calculation, because it requires no division by 4 (or 12), and the procedure is easy to remember because of its repeated use of the "odd + 11" rule.

Extending this to get the Doomsday, the procedure is often described as accumulating a running total $T$ in six steps, as follows:

Let $T$ be the year's last two digits.
If $T$ is odd, add 11.
Now let $T = T / 2$ .
If $T$ is odd, add 11.
Now let $T = 7 - (T mod 7)$ .
Count forward $T$ days from the century's anchor day to get the year's Doomsday.

Applying this method to the year 2005, for example, the steps as outlined would be:

$T = 5$
$T = 5 + 11 = 16$ (adding 11 because $T$ is odd)
$T = 16 / 2 = 8$
$T = 8$ (do nothing since $T$ is even)
$T = 7 - (8 mod 7) = 7 - 1 = 6$
Doomsday for 2005 = 6 + Tuesday = Monday

The explicit formula for the odd+11 method is:

7- \left[\frac{y+11(y\,\bmod 2)}{2} + 11 \left(\frac{y+11(y\,\bmod 2)}{2}\bmod 2\right)\right] \bmod 7

Although this expression looks daunting and complicated, it is actually simple^[7] because of a common subexpression $y + 11(y mod 2) / 2$ that only needs to be calculated once.

Dominical letter method

A year's doomsday (DD) can also be determined from a year's dominical letter (DL).

DD = (3 - DL) mod 7

Note: A = 1, B = 2, ..., G = 0.

For the year 1966 the dominical letter is B, so the doomsday DD = 3 – 2 = 1 = Monday.

Doomsday	Dominical letter
Sunday	C, DC
Monday	B, CB
Tuesday	A, BA
Wednesday	G, AG
Thursday	F, GF
Friday	E, FE
Saturday	D, ED

Finding a century's anchor day

For the Gregorian calendar:

5 \times (c mod 4) mod 7 +

Tuesday = anchor.

For the Julian calendar:

6 \times (c mod 7) mod 7 +

Sunday = anchor.

Note: $c = ⌊ year / 100 ⌋$ .

Overview of all Doomsdays

Month	Dates	Week numbers *
January (common years)	3, 10, 17, 24, 31	1–5
January (leap years)	4, 11, 18, 25	1–4
February (common years)	7, 14, 21, 28	6–9
February (leap years)	1, 8, 15, 22, 29	5–9
March	7, 14, 21, 28	10–13
April	4, 11, 18, 25	14–17
May	2, 9, 16, 23, 30	18–22
June	6, 13, 20, 27	23–26
July	4, 11, 18, 25	27–30
August	1, 8, 15, 22, 29	31–35
September	5, 12, 19, 26	36–39
October	3, 10, 17, 24, 31	40–44
November	7, 14, 21, 28	45–48
December	5, 12, 19, 26	49–52

* In leap years the $n$ th Doomsday is in ISO week $n$ . In common years the day after the $n$ th Doomsday is in week $n$ . Thus in a common year the week number on the Doomsday itself is one less if it is a Sunday, i.e. in a common year starting on Friday.

Computer formula for the Doomsday of a year

For computer use, the following formulas for the Doomsday of a year are convenient.

For the Gregorian calendar:

\mbox{Doomsday} = \mbox{Tuesday} + y + \left\lfloor\frac{y}{4}\right\rfloor - \left\lfloor\frac{y}{100}\right\rfloor + \left\lfloor\frac{y}{400}\right\rfloor = \mbox{Tuesday} + 5\times (y\bmod 4) + 4\times (y\bmod 100) + 6\times (y\bmod 400)

For example, the year 2009 has a doomsday of Saturday under the Gregorian calendar (the currently accepted calendar), since

\mbox{Saturday (6)} \bmod 7 = \mbox{Tuesday (2)} + 2009 + \left\lfloor\frac{2009}{4}\right\rfloor - \left\lfloor\frac{2009}{100}\right\rfloor + \left\lfloor\frac{2009}{400}\right\rfloor

As another example, the year 1946 has a doomsday of Thursday, since

\mbox{Thursday (4)} \bmod 7 = \mbox{Tuesday (2)} + 1946 + \left\lfloor\frac{1946}{4}\right\rfloor - \left\lfloor\frac{1946}{100}\right\rfloor + \left\lfloor\frac{1946}{400}\right\rfloor

For the Julian calendar:

\mbox{Doomsday} = \mbox{Sunday} + y + \left\lfloor\frac{y}{4}\right\rfloor = \mbox{Sunday}+ 5\times (y\bmod 4) + 3\times (y\bmod 7)

The formulas apply also for the proleptic Gregorian calendar and the proleptic Julian calendar. They use the floor function and astronomical year numbering for years BC.

For comparison, see the calculation of a Julian day number.

400-year cycle of Doomsdays

Julian centuries ——— Gregorian centuries \ Years	-1600J -900J -200J 500J 1200J 1900J 2600J 3300J — -1600 -1200 -800 -400 0 400 800 1200 1600 2000 2400 2800 3200 3600	-1500J -800J -100J 600J 1300J 2000J 2700J 3400J —	-1400J -700J 0J 700J 1400J 2100J 2800J 3500J — -1500 -1100 -700 -300 100 500 900 1300 1700 2100 2500 2900 3300 3700	-1300J -600J 100J 800J 1500J 2200J 2900J 3600J —	-1200J -500J 200J 900J 1600J 2300J 3000J 3700J — -1400 -1000 -600 -200 200 600 1000 1400 1800 2200 2600 3000 3400 3800	-1100J -400J 300J 1000J 1700J 2400J 3100J 3800J —	-1000J -300J 400J 1100J 1800J 2500J 3200J 3900J — -1300 -900 -500 -100 300 700 1100 1500 1900 2300 2700 3100 3500 3900
00 28 56 84	Tue.	Mon.	Sun.	Sat.	Fri.	Thu.	Wed.
01 29 57 85	Wed.	Tue.	Mon.	Sun.	Sat.	Fri.	Thu.
02 30 58 86	Thu.	Wed.	Tue.	Mon.	Sun.	Sat.	Fri.
03 31 59 87	Fri.	Thu.	Wed.	Tue.	Mon.	Sun.	Sat.
04 32 60 88	Sun.	Sat.	Fri.	Thu.	Wed.	Tue.	Mon.
05 33 61 89	Mon.	Sun.	Sat.	Fri.	Thu.	Wed.	Tue.
06 34 62 90	Tue.	Mon.	Sun.	Sat.	Fri.	Thu.	Wed.
07 35 63 91	Wed.	Tue.	Mon.	Sun.	Sat.	Fri.	Thu.
08 36 64 92	Fri.	Thu.	Wed.	Tue.	Mon.	Sun.	Sat.
09 37 65 93	Sat.	Fri.	Thu.	Wed.	Tue.	Mon.	Sun.
10 38 66 94	Sun.	Sat.	Fri.	Thu.	Wed.	Tue.	Mon.
11 39 67 95	Mon.	Sun.	Sat.	Fri.	Thu.	Wed.	Tue.
12 40 68 96	Wed.	Tue.	Mon.	Sun.	Sat.	Fri.	Thu.
13 41 69 97	Thu.	Wed.	Tue.	Mon.	Sun.	Sat.	Fri.
14 42 70 98	Fri.	Thu.	Wed.	Tue.	Mon.	Sun.	Sat.
15 43 71 99	Sat.	Fri.	Thu.	Wed.	Tue.	Mon.	Sun.
16 44 72	Mon.	Sun.	Sat.	Fri.	Thu.	Wed.	Tue.
17 45 73	Tue.	Mon.	Sun.	Sat.	Fri.	Thu.	Wed.
18 46 74	Wed.	Tue.	Mon.	Sun.	Sat.	Fri.	Thu.
19 47 75	Thu.	Wed.	Tue.	Mon.	Sun.	Sat.	Fri.
20 48 76	Sat.	Fri.	Thu.	Wed.	Tue.	Mon.	Sun.
21 49 77	Sun.	Sat.	Fri.	Thu.	Wed.	Tue.	Mon.
22 50 78	Mon.	Sun.	Sat.	Fri.	Thu.	Wed.	Tue.
23 51 79	Tue.	Mon.	Sun.	Sat.	Fri.	Thu.	Wed.
24 52 80	Thu.	Wed.	Tue.	Mon.	Sun.	Sat.	Fri.
25 53 81	Fri.	Thu.	Wed.	Tue.	Mon.	Sun.	Sat.
26 54 82	Sat.	Fri.	Thu.	Wed.	Tue.	Mon.	Sun.
27 55 83	Sun.	Sat.	Fri.	Thu.	Wed.	Tue.	Mon.

Since in the Gregorian calendar there are 146097 days, or exactly 20871 seven-day weeks, in 400 years, the anchor day repeats every four centuries. For example, the anchor day of 1700–1799 is the same as the anchor day of 2100–2199, i.e. Sunday.

The full 400-year cycle of Doomsdays is given in the table to the right. The centuries are for the Gregorian and proleptic Gregorian calendar, unless marked with a J for Julian. The Gregorian leap years are highlighted.

Negative years use astronomical year numbering. Year 25BC is −24, shown in the column of −100J (proleptic Julian) or −100 (proleptic Gregorian), at the row 76.

**Frequency of Gregorian Doomsday in the 400-year cycle per weekday and year type**
	Sunday	Monday	Tuesday	Wednesday	Thursday	Friday	Saturday	Total
Non-leap years	43	43	43	43	44	43	44	303
Leap years	13	15	13	15	13	14	14	97
Total	56	58	56	58	57	57	58	400

A leap year with Monday as Doomsday means that Sunday is one of 97 days skipped in the 497-day sequence. Thus the total number of years with Sunday as Doomsday is 71 minus the number of leap years with Monday as Doomsday, etc. Since Monday as Doomsday is skipped across 29 February 2000 and the pattern of leap days is symmetric about that leap day, the frequencies of Doomsdays per weekday (adding common and leap years) are symmetric about Monday. The frequencies of Doomsdays of leap years per weekday are symmetric about the Doomsday of 2000, Tuesday.

The frequency of a particular date being on a particular weekday can easily be derived from the above (for a date from 1 January – 28 February, relate it to the Doomsday of the previous year).

For example, 28 February is one day after Doomsday of the previous year, so it is 58 times each on Tuesday, Thursday and Sunday, etc. 29 February is Doomsday of a leap year, so it is 15 times each on Monday and Wednesday, etc.

28-year cycle

Regarding the frequency of Doomsdays in a Julian 28-year cycle, there are 1 leap year and 3 common years for every weekday, the latter 6, 17 and 23 years after the former (so with intervals of 6, 11, 6, and 5 years; not evenly distributed because after 12 years the day is skipped in the sequence of Doomsdays). The same cycle applies for any given date from 1 March falling on a particular weekday.

For any given date up to 28 February falling on a particular weekday, the 3 common years are 5, 11, and 22 years after the leap year, so with intervals of 5, 6, 11, and 6 years. Thus the cycle is the same, but with the 5-year interval after instead of before the leap year.

Thus, for any date except 29 February, the intervals between common years falling on a particular weekday are 6, 11, 11. See e.g. at the bottom of the page Common year starting on Monday the years in the range 1906–2091.

For 29 February falling on a particular weekday, there is just one in every 28 years, and it is of course a leap year.

Julian calendar

The Gregorian calendar accurately lines up with astronomical events such as solstices. In 1582 this modification of the Julian calendar was first instituted. In order to correct for calendar drift, 10 days were skipped, so Doomsday moved back 10 days (i.e. 3 days): Thursday 4 October (Julian, Doomsday is Wednesday) was followed by Friday 15 October (Gregorian, Doomsday is Sunday). The table includes Julian calendar years, but the algorithm is for the Gregorian and proleptic Gregorian calendar only.

Note that the Gregorian calendar was not adopted simultaneously in all countries, so for many centuries, different regions used different dates for the same day.

Full examples

Example 1 (1985)

Suppose you want to know the day of the week of September 18, 1985. You begin with the century's anchor day, Wednesday. To this, we'll add three things, called $a$ , $b$ , and $c$ above:

$a$ is the floor of $85 / 12$ , which is 7.
$b$ is $85 mod 12$ , which is $1$ .
$c$ is the floor of $b / 4$ , which is 0.

This yields $a + b + c = 8$ . Counting 8 days from Wednesday, we reach Thursday, which is the Doomsday in 1985. (Using numbers: In modulo 7 arithmetic, 8 is congruent to 1. Because the century's anchor day is Wednesday (index 3), and 3 + 1 = 4, Doomsday in 1985 was Thursday (index 4).) We now compare September 18 to a nearby Doomsday, September 5. We see that the 18th is 13 past a Doomsday, i.e. one day less than two weeks. Hence, the 18th was a Wednesday (the day preceding Thursday). (Using numbers: In modulo 7 arithmetic, 13 is congruent to 6 or, more succinctly, −1. Thus, we take one away from the Doomsday, Thursday, to find that September 18, 1985 was a Wednesday.)

Example 2 (other centuries)

Suppose that you want to find the day of week that the American Civil War broke out at Fort Sumter, which was April 12, 1861. The anchor day for the century was 99 days after Thursday, or, in other words, Friday (calculated as $(18 + 1) \times 5 + ⌊ 18 / 4 ⌋$ ; or just look at the chart, above, which lists the century's anchor days). The digits 61 gave a displacement of six days so Doomsday was Thursday. Therefore, April 4 was Thursday so April 12, eight days later, was a Friday.

References

↑ John Horton Conway, "Tomorrow is the Day After Doomsday", Eureka, volume 36, pages 28–31, October 1973.
↑ Richard Guy, John Horton Conway, Elwyn Berlekamp : "Winning Ways: For Your Mathematical Plays, Volume. 2: Games in Particular", pages 795–797, Academic Press, London, 1982, ISBN 0-12-091102-7.
↑ Lewis Carroll, "To Find the Day of the Week for Any Given Date", Nature, March 31, 1887. doi:10.1038/035517a0
↑ Martin Gardner, "The Universe in a Handkerchief: Lewis Carroll's Mathematical Recreations, Games, Puzzles, and Word Plays", pages 24–26, Springer-Verlag, 1996
↑ Alpert, Mark. "Not Just Fun and Games", Scientific American, April, 1999. doi:10.1038/scientificamerican0499-40
↑ "Doomsday Algorithm". rudy.ca. Retrieved 20 June 2015.
1 2 3 Chamberlain Fong, Michael K. Walters: "Methods for Accelerating Conway's Doomsday Algorithm (part 2)", 7th International Congress on Industrial and Applied Mathematics (2011)

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Doomsday rule

Doomsdays for some contemporary years

Memorable dates that always land on Doomsday

Examples

Finding a year's Doomsday

Why it works

The "odd + 11" method

Dominical letter method

Finding a century's anchor day

Overview of all Doomsdays

Computer formula for the Doomsday of a year

400-year cycle of Doomsdays

28-year cycle

Julian calendar

Full examples

Example 1 (1985)

Example 2 (other centuries)

See also

References

External links