Lee Township, Brown County, Illinois

Lee Township
Township

Location in Brown County

Brown County's location in Illinois
Coordinates: 39°58′30″N 90°51′01″W / 39.97500°N 90.85028°W / 39.97500; -90.85028Coordinates: 39°58′30″N 90°51′01″W / 39.97500°N 90.85028°W / 39.97500; -90.85028
Country United States
State Illinois
County Brown
Established November 8, 1853
Area
  Total 37.67 sq mi (97.6 km2)
  Land 37.63 sq mi (97.5 km2)
  Water 0.04 sq mi (0.1 km2)  0.11%
Elevation 728 ft (222 m)
Population (2010)
  Total 326
  Density 8.7/sq mi (3.4/km2)
Time zone CST (UTC-6)
  Summer (DST) CDT (UTC-5)
ZIP codes 62353, 62375
GNIS feature ID 0429239

Lee Township is one of nine townships in Brown County, Illinois, USA. As of the 2010 census, its population was 326 and it contained 158 housing units.[1]

Geography

According to the 2010 census, the township has a total area of 37.67 square miles (97.6 km2), of which 37.63 square miles (97.5 km2) (or 99.89%) is land and 0.04 square miles (0.10 km2) (or 0.11%) is water.[1]

Cities

Unincorporated towns

Cemeteries

The township contains these seven cemeteries: Ausmus, Buckhorn, Cleaves, Fargo, Howe, Lee and Orton.

Major highways

Airports and landing strips

School districts

Political districts

References

  1. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-28.

External links

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