Maria Isabel de Alcântara, Countess of Iguaçu

The Countess of Iguaçu, c. 1852. Painting by Ferdinand Krumholz
Maria Isabel holding one of her children, c. 1852

Maria Isabel de Alcântara Bourbon[1] (São Paulo, 28 February 1830 – 5 September 1896)[1] was the third daughter (fifth child) of Emperor Pedro I of Brazil and his mistress, Domitila de Castro, Marchioness of Santos.

Maria Isabel received the same name as her second sister, the Duchess of Ceara, who died in 1828.[2] She was never given any titles by her father due to his marriage to Amélie of Leuchtenberg. Still, Pedro I acknowledged her as his daughter in his will but gave her no share of his state, except asking for his widow to aid in her education and upbringing.[3] He had wished that she be given a good European education like her oldest sister, the Duchess of Goiás. However, the Marchioness declined to send the girl to Europe.[4]

On 2 September 1848, at the age of eighteen, Maria Isabel married Pedro Caldeira Brant, the Count of Iguaçu, son of Felisberto Caldeira Brant, Marquis of Barbacena.[5] At their wedding, Maria Isabel became the second Countess of Iguaçu. The couple had seven children:

She died on 5 September 1896, at sixty-six years of age, in São Paulo.[1]

References

  1. 1 2 3 Veiga, Edison (27 June 2015). "Filha de d. Pedro foi sepultada no Cemitério da Consolação" (in Portuguese). São Paulo: O Estado de S. Paulo. Retrieved 29 June 2015.
  2. ↑ D. Maria Isabel de Alcântara Brasileira, 1.ª duquesa de Ceará – GeneAll.net
  3. ↑ Rangel 1928, p. 447.
  4. ↑ Lewin 2003, p. 155-156.
  5. ↑ Viana 1968, p. 206.

Bibliography


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