Palmyra, Hunterdon County, New Jersey

Not to be confused with Palmyra, New Jersey in Burlington County.
Palmyra, New Jersey
Unincorporated community
Palmyra, New Jersey

Palmyra's location in Hunterdon County (Inset: Hunterdon County in New Jersey)

Palmyra, New Jersey

Location within the state of New Jersey

Coordinates: 40°33′41″N 75°0′55″W / 40.56139°N 75.01528°W / 40.56139; -75.01528Coordinates: 40°33′41″N 75°0′55″W / 40.56139°N 75.01528°W / 40.56139; -75.01528
Country United States
State New Jersey
County Hunterdon
Township Alexandria
Elevation[1] 463 ft (141 m)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
GNIS feature ID 879105[1]

Palmyra is an unincorporated community located within Alexandria Township, in Hunterdon County, New Jersey, United States.[1][2][3]

References

This article is issued from Wikipedia - version of the Sunday, February 01, 2015. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.