Romanian general election, 1928

General elections were held in Romania on 12 December December 1928.^[1] The Chamber of Deputies was elected on 12 December, whilst the Senate was elected in three stages on 15, 17 and 19 December.^[1] The result was a victory for the National Peasants' Party-led alliance, which won 348 of the 387 seats in the Chamber of Deputies and 105 of the 110 seats in the Senate.^[2] Of the 348 Chamber seats won by the alliance, the National Peasants' Party won 326, the Social Democratic Party won 9, the German Party won 8, the Hungarian People's Party won 2 and three were won by other parties.^[2] It is generally regarded as the freest election ever held in Romania until the 1990s.^[3]

Results

Party	Chamber				Senate
	Votes	%	Seats	+/–	Votes	%	Seats	+/–
National Peasants' Party-led alliance	2,208,922	79.2	348	+294			105	+88
National Liberal Party	185,939	6.7	13	–305			0	–92
Magyar Party	172,099	6.2	16	New			3	New
National Party–People's Party	70,790	2.5	5	+5			0	0
Peasants' Party–Lupu	70,506	2.5	5	New			0	New
Peasant Workers' Bloc	38,851	1.4	0	New			0	New
National-Christian Defense League	32,273	1.2	0	New			0	New
Other parties	8,051	0.3	0	–			3	–
Jewish Party			0	–			2	New
Invalid/blank votes	53,249	–	–	–		–	–	–
Total	2,840,680	100	387	0			110	–3
Registered voters/turnout	3,671,352	77.4	–	–			–	–
Source: Nohlen & Stöver

References

1. Nohlen, D & Stöver, P (2010) Elections in Europe: A data handbook, p1591 ISBN 978-3-8329-5609-7
2. Nohlen & Stöver, pp1610-1611
3. Romania from Encyclopedia Britannica.