Sędzin

Sędzin
Village
Sędzin
Coordinates: 52°44′N 18°34′E / 52.733°N 18.567°E / 52.733; 18.567
Country  Poland
Voivodeship Kuyavian-Pomeranian
County Aleksandrów
Gmina Zakrzewo
Population (approx.) 600

Sędzin [ˈsɛnd͡ʑin] is a village in the administrative district of Gmina Zakrzewo, within Aleksandrów County, Kuyavian-Pomeranian Voivodeship, in north-central Poland.[1] It lies 18 kilometres (11 mi) south-west of Aleksandrów Kujawski and 34 km (21 mi) south of Toruń.

The village has an approximate population of 600.

References


Coordinates: 52°44′N 18°34′E / 52.733°N 18.567°E / 52.733; 18.567


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