San Andrés Teotilalpam
| San Andrés Teotilalpam | |
|---|---|
| Municipality and town | |
  San Andrés Teotilalpam Location in Mexico | |
| Coordinates: 17°57′N 96°39′W / 17.950°N 96.650°WCoordinates: 17°57′N 96°39′W / 17.950°N 96.650°W | |
| Country |
 Mexico |
| State | Oaxaca |
| Area | |
| • Total | 102.07 km2 (39.41 sq mi) |
| Population (2005) | |
| • Total | 4,255 |
| Time zone | Central Standard Time (UTC-6) |
| • Summer (DST) | Central Daylight Time (UTC-5) |
San Andrés Teotilalpam is a town and municipality in Oaxaca in south-western Mexico. The municipality covers an area of 102.07 km². It is part of Cuicatlán District in the north of the Cañada Region.
As of 2005, the municipality had a total population of 4255.[1]
References
- ↑ "San Andrés Teotilalpam". Enciclopedia de los Municipios de México. Instituto Nacional para el Federalismo y el Desarrollo Municipal. Retrieved June 12, 2009.
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