Sherman Township, Antelope County, Nebraska
Sherman Township | |
---|---|
Township | |
Location in Antelope County | |
Coordinates: 42°23′27″N 098°14′27″W / 42.39083°N 98.24083°WCoordinates: 42°23′27″N 098°14′27″W / 42.39083°N 98.24083°W | |
Country | United States |
State | Nebraska |
County | Antelope |
Area | |
• Total | 35.81 sq mi (92.75 km2) |
• Land | 35.77 sq mi (92.65 km2) |
• Water | 0.04 sq mi (0.10 km2) 0.11% |
Elevation | 1,755 ft (535 m) |
Population (2010) | |
• Total | 103 |
• Density | 3/sq mi (1.1/km2) |
GNIS feature ID | 0838246 |
Sherman Township is one of twenty-four townships in Antelope County, Nebraska, United States. The population was 103 at the 2010 census.[1]
See also
References
- ↑ "Geographic Identifiers: 2010 Demographic Profile Data (G001): Sherman township, Antelope County, Nebraska". U.S. Census Bureau, American Factfinder. Retrieved June 27, 2013.
External links
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