Suchy Dwór, Pomeranian Voivodeship

Suchy Dwór
Village
Suchy Dwór
Coordinates: 54°34′32″N 18°27′53″E / 54.57556°N 18.46472°E / 54.57556; 18.46472
Country Poland Poland
Voivodeship Pomeranian
County Puck
Gmina Kosakowo
Population 888

Suchy Dwór [ˈsuxɨ ˈdvur] is a village in the administrative district of Gmina Kosakowo, within Puck County, Pomeranian Voivodeship, in northern Poland.[1] It lies approximately 2 kilometres (1 mi) south-west of Kosakowo, 15 km (9 mi) south of Puck, and 26 km (16 mi) north-west of the regional capital Gdańsk.

For details of the history of the region, see History of Pomerania.

The village has a population of 888.

References


Coordinates: 54°34′32″N 18°27′53″E / 54.57556°N 18.46472°E / 54.57556; 18.46472


This article is issued from Wikipedia - version of the Tuesday, September 17, 2013. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.