United States presidential election in Delaware, 1852

Main article: United States presidential election, 1852

Elections in Delaware

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Lieutenant gubernatorial elections
2008 · 2012

Wilmington
Mayoral elections
2012

The 1852 United States presidential election in Delaware took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Delaware by a margin of 0.19%.

Results

United States presidential election in Delaware, 1852^[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Democratic	Franklin Pierce of New Hampshire	William R. King of Alabama	6,318	49.85%	3	100.00%
	Whig	Winfield Scott of New Jersey	William Alexander Graham of North Carolina	6,293	49.66%	0	0.00%
	Free Soil	John P. Hale of New Hampshire	George Washington Julian of Indiana	62	0.49%	0	0.00%
Total				12,673	100.00%	3	100.00%

References

↑ "1852 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 17 March 2015.

State Results of the 1852 U.S. presidential election

Candidates	Franklin Pierce Winfield Scott John P. Hale

General articles	Election timeline

Local results	Alabama Arkansas California Connecticut Delaware Georgia Illinois Indiana Iowa Kentucky Louisiana Maine Maryland Massachusetts Michigan Mississippi Missouri New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Texas Vermont Virginia Wisconsin

Other 1852 elections	House Senate Gubernatorial

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