United States presidential election in Rhode Island, 2000

United States presidential election in Rhode Island, 2000
Rhode Island
November 7, 2000

 
Nominee Al Gore George W. Bush Ralph Nader
Party Democratic Republican Green
Home state Tennessee Texas Connecticut
Running mate Joe Lieberman Dick Cheney Winona LaDuke
Electoral vote 4 0 0
Popular vote 249,508 130,555 25,052
Percentage 60.99% 31.91% 6.12%

County Results
  Gore—60-70%
  Gore—50-60%

Rhode Island is one of the most reliable blue states in the country. This state was Al Gore's best performance in the country, winning with over 60% of the vote. Gore won all the counties and won all but two townships. Nader took in over 6% in this state, one of his best showings.[1]

Primaries

Democratic Primary (March 7)

Al Gore won the primary from Rhode Island and won every county except Bristol County and Washington County. The state was worth 32 delegates.

Al Gore Bill Bradley other
26,801 19,000 1,043
57% 41% 2%

Republican Primary (March 7)

This primary was one of the very few states Senator John McCain won in the 2000 Republican primaries against George W. Bush. He won every single county, town, and city in the state. He also won all of the state's 14 delegates.

John McCain George W. Bush others
21,754 13,170 1,196
60% 36% 4%

General Election Results by County

County Al Gore George W. Bush Others
Providence 65.26% 142,469 28.12% 61,378 6.62% 14,461
Bristol 57.68% 13,424 35.99% 8,375 6.33% 1,473
Newport 54.94% 20,790 37.68% 14,258 7.38% 2,790
Washington 52.58% 29,560 37.80% 21,253 9.62% 5,411
Kent 58.89% 43,265 34.42% 25,291 6.69% 4,914

By congressional district

Gore won both congressional districts.

District Bush Kerry Representative
1st 31% 63% Patrick J. Kennedy
2nd 33% 60% Robert Weygand
James Langevin

References

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