Belgian general election, 1886

Belgian general election, 1886
Belgium
8 June 1886 (1886-06-08)

69 of the 138 seats in the Chamber of Representatives
70 seats needed for a majority
  First party Second party
 
Party Catholic Liberal
Last election 86 seats 52 seats
Seats won 98 40
Seat change Increase12 Decrease12
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Partial general elections were held in Belgium on 8 June 1886.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 98 of the 138 seats.[2]

Under the alternating system, elections were only held in four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders.

Results

Chamber of Representatives

Party Votes % Seats
Won Total +/–
Liberal Party18,96551.33740–12
Catholic Party17,97948.73298+12
Invalid/blank votes
Total36,944100691380
Registered voters/turnout57,962
Source: Mackie & Rose,[3] Sternberger et al

References

  1. Codebook Constituency-level Elections Archive, 2003
  2. 1 2 Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105
  3. Thomas T Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, pp50–51
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