Iowa Republican caucuses, 1996

Iowa Republican caucuses, 1996

February 12, 1996

Nominee Bob Dole Pat Buchanan Lamar Alexander Party Republican Republican Republican Home state Kansas Virginia Tennessee Popular vote 25,461 22,578 17,052 Percentage 26.31% 23.33% 17.62%

Election results by county. Red denotes counties won by Dole, Green denotes those won by Buchanan, and Blue denotes those won by Alexander.

The 1996 Iowa Republican caucuses were held on February 12, 1996. The Iowa Republican caucuses are an unofficial primary, with the delegates to the state convention selected proportionally via a straw poll. The Iowa caucuses marked the traditional formal start of the delegate selection process for the 1996 United States presidential election.

Prior to the 1996 caucuses, as in previous election cycles with a competitive presidential race, an unofficial Ames Straw Poll was held, on August 19, 1995. The official one, electing delegates to the state convention, was held on February 12, 1996, the same day as the Democratic contest. In the Ames Straw Poll, Bob Dole and Phil Gramm tied with 24% of the vote each. In the February 1996 caucuses, Dole finished first with 26% of the vote.

February 1996 procedure

Unlike the Democratic caucus, the Republican Party does not use voting rounds or have minimum requirements for a percent of votes. The Republican version is done with a straw vote of those attending the caucus. This vote is sometimes done by a show of hands or by dividing themselves into groups according to candidate. However, officially it is done with voters receiving a blank piece of paper with no names on it, and the voter writing a name and placing it in a ballot box.

Following the straw poll, delegates are then elected from the remaining participants in the room, as most voters leave once their vote is cast. All delegates are officially considered unbound, but media outlets either apportion delegates proportionally or apportion them in terms of winner-take-all by counties. In precincts that elect only one delegate, the delegate is chosen by majority vote and the vote must be by paper ballot. The state party strongly urges that delegates reflect the results of the preference poll, but there is no obligation that they do so.

Ames Straw Poll

The 1996 Ames straw poll was held at Iowa State University (Ames)'s Hilton Coliseum on August 19, 1995. This was primarily a fundraising event for the state's Republican Party, and only Iowa residents who paid the $25^[1] price for a ticket were eligible to vote. Tickets were available through the various presidential campaigns and the Iowa Republican Party's headquarters.

In general, the candidates bought large blocks of tickets and gave them out for free to whoever agreed to go and vote for that candidate. The candidates also rented buses to transport voters to Ames.

Bob Dole and Phil Gramm tied for the win with 24% of the vote each, followed by Pat Buchanan (18%), Lamar Alexander (11%), and Alan Keyes (8%). Five other candidates shared the remaining 15% of the vote.

Results of the February 1996 caucuses

Iowa Republican caucuses, February 12, 1996[2]
Candidate	Votes	Percentage
Bob Dole	25,461	26.31%
Pat Buchanan	22,578	23.33%
Lamar Alexander	17,052	17.62%
Steve Forbes	9,861	10.19%
Phil Gramm	9,055	9.36%
Alan Keyes	7,219	7.46%
Richard Lugar	3,595	3.72%
Morry Taylor	1,381	1.43%
Uncommitted	431	0.45%
Robert K. Dornan	129	0.13%
Total:	96,762	100.0%

Three candidates won majorities or pluralities in the individual counties: Bob Dole, Pat Buchanan, and Lamar Alexander. Buchanan used the momentum from his better-than-expected second-place showing in the Iowa caucuses to vault to a narrow win in the New Hampshire primary eight days later.

See also

• Iowa caucuses
• Republican Party (United States) presidential primaries, 1996

References

1. Bush wins Iowa GOP straw poll August 19, 1995
2. "1996 Presidential Republican Primary Election Results - Iowa". Retrieved 1 February 2012.