United States Senate election in Wyoming, 1988

United States Senate election in Wyoming, 1988

November 8, 1988

Nominee Malcolm Wallop John P. Vinich Party Republican Democratic Popular vote 91,143 89,821 Percentage 50.37% 49.64%

U.S. Senator before election Malcolm Wallop Republican Elected U.S. Senator Malcolm Wallop Republican

The 1988 United States Senate election in Wyoming took place on November 8, 1988. Incumbent Republican U.S. Senator Malcolm Wallop ran for re-election to a fourth term, and was narrowly re-elected, defeating the Democratic candidate John Vinich by a margin of a little over 1,300 votes.^[1]

Major candidates

Democratic

• John P. Vinich, Wyoming State Senator

Republican

• Malcolm Wallop, incumbent U.S. Senator

General election

Despite being a reliably Republican state, Vinich, a Democrat, was able to impressively compete with Wallop. During the campaign, Wallop attacked Vinich as being a tax-and-spend liberal who was beholden to labor and anti-business.^[1] Vinich, in turn, cited his "A" score he got from the National Rifle Association due to his votes in the Wyoming Legislature to counter Wallop's attacks, and possibly attract conservative voters.^[1]

Results

General election results[2]
Party		Candidate	Votes	%	±%
	Republican	Malcolm Wallop (inc.)	91,143	50.37%
	Democratic	John P. Vinich	89,821	49.64%

References

1. "THE 1988 ELECTIONS: West; WYOMING". New York Times. November 9, 1988. Retrieved May 16, 2015.
2. "Our Campaigns - WY US Senate Race - Nov 08, 1988". ourcampaigns.com. Retrieved May 10, 2015.