United States presidential election in Wyoming, 1996

United States presidential election in Wyoming, 1996

November 5, 1996

Nominee Bob Dole Bill Clinton Ross Perot Party Republican Democratic Reform Home state Kansas Arkansas Texas Running mate Jack Kemp Al Gore Patrick Choate Electoral vote 3 0 0 Popular vote 105,388 77,934 25,928 Percentage 49.8% 36.8% 12.3%

County Results   Clinton—40-50%   Dole—40-50%   Dole—50-60%   Dole—60-70%

President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

The 1996 United States presidential election in Wyoming took place on November 5, 1996 as part of the 1996 United States presidential election. Voters chose 9 representatives, or electors to the Electoral College, who voted for President and Vice President.

Wyoming was won by Senator Bob Dole (R-KS), with Dole winning 49.81% to 36.84% over President Bill Clinton (D) by a margin of 12.97%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 12.25% of the popular vote .^[1]

Results

United States presidential election in Wyoming, 1996
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Republican	Bob Dole	Jack Kemp	105,388	49.81%	3
	Democratic	Bill Clinton (incumbent)	Al Gore	77,934	36.84%	0
	Reform	Ross Perot	Patrick Choate	25,928	12.25%	0
	Libertarian	Harry Browne	Jo Jorgensen	1,739	0.82%	0
	Natural Law	Dr. John Hagelin	Dr. V. Tompkins	582	0.28%	0

References

1. http://uselectionatlas.org/RESULTS/index.html

See also