United States presidential election in Montana, 1996

United States presidential election in Montana, 1996

November 5, 1996

Nominee Bob Dole Bill Clinton Ross Perot Party Republican Democratic Reform Home state Kansas Arkansas Texas Running mate Jack Kemp Al Gore Patrick Choate Electoral vote 3 0 0 Popular vote 179,652 167,922 55,229 Percentage 44.11% 41.23% 13.56%

President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

The 1996 United States presidential election in Montana took place on November 5, 1996. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Montana voted for Senate Majority Leader Bob Dole over President Bill Clinton by a slim margin of 2.88%.^[1] Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 13.56% of the popular vote in Montana.^[2]

Results

United States presidential election in Montana, 1996[3]
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Republican	Bob Dole	Jack Kemp	179,652	44.11%	3
	Democratic	Bill Clinton	Al Gore	167,922	41.23%	0
	Reform	Ross Perot	Patrick Choate	55,229	13.56%	0
	Libertarian	Harry Browne	Jo Jorgensen	2,526	0.62%	0
	Natural Law (write in)	John Hagelin	Mike Tompkins	1,754	0.43%	0
	Constitutional (write in)	Howard Phillips	Herbert Titus	152	0.04%	0
	(write in)	Charles E. Collins	Rosemary Giumarra	20	0.00%	0
	Independent (write in)	Write-ins		5	0.00	0
	Socialist (write in)	Mary Cal Hollis	Eric Chester	1	0.00	0

References

1. http://uselectionatlas.org/RESULTS/index.html
2. http://uselectionatlas.org/RESULTS/index.html
3. http://uselectionatlas.org/RESULTS/index.html