United States presidential election in Montana, 1896

United States presidential election in Montana, 1896

November 3, 1896

Nominee William Jennings Bryan William McKinley Party Democratic Republican Home state Nebraska Ohio Running mate Arthur Sewall Garret Hobart Electoral vote 3 0 Popular vote 42,628 10,509 Percentage 79.93% 19.71%

County results

President before election Grover Cleveland Democratic Elected President William McKinley Republican

The 1896 United States presidential election in Montana took place on November 3, 1896 throughout 45 states. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Montana overwhelmingly voted for the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan over the Republican nominee, former governor of Ohio William McKinley. Bryan won Montana by a landslide margin of 60.22%.

Bryan's support for many Populist goals resulted in him being nominated by both the Democratic Party and the People's Party (Populists), though with different running mates. One electoral vote from Montana was cast for the Populist Bryan-Watson ticket with Thomas E. Watson as Vice-President and two votes were cast for the Bryan-Sewall ticket.

Results

United States presidential [1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	William Jennings Bryan	42,628	79.93%	3
	Republican	William McKinley	10,509	19.71%	0
	Prohibition	Joshua Levering	193	0.36%	0

References

1. http://uselectionatlas.org/RESULTS/index.html