United States presidential election in Montana, 1892

United States presidential election in Montana, 1892

November 8, 1892

Nominee Benjamin Harrison Grover Cleveland James Weaver Party Republican Democratic Populist Home state Indiana New York Iowa Running mate Whitelaw Reid Adlai Stevenson James Field Electoral vote 3 0 0 Popular vote 18,871 17,690 7,338 Percentage 42.44% 39.79% 16.50%

County results

President before election Benjamin Harrison Republican Elected President Grover Cleveland Democratic

The 1892 United States presidential election in Montana took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Montana voted for the Republican nominee, incumbent President Benjamin Harrison, over the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term and over the People's Party (Populists) nominee James B. Weaver. Harrison won Montana by a margin of 2.65%.

This was the first time that Montana voted in a national electtion.

Results

United States presidential election in Montana, 1892[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Benjamin Harrison (incumbent)	18,871	42.44%	3
	Democratic	Grover Cleveland	17,690	39.79%	0
	People's	James Weaver	7,338	16.50%	0
	Prohibition	John Bidwell	562	1.26%	0
Totals			44,461	99.99%	3

References

1. "1892 Presidential General Election Results - Montana". U.S. Election Atlas. Retrieved 1 August 2012.