United States presidential election in Montana, 1948

United States presidential election in Montana, 1948

Nominee Harry S. Truman Thomas E. Dewey Party Democratic Republican Home state Missouri New York Running mate Alben W. Barkley Earl Warren Electoral vote 4 0 Popular vote 119,071 96,770 Percentage 53.09% 43.15%

County results

President before election Harry S. Truman Democratic Elected President Harry S. Truman Democratic

The 1948 United States presidential election in Montana took place on November 2, 1948, throughout the continuous 48 states. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

Montana voted for the Democratic nominee, President Harry Truman, over the Republican nominee, New York Governor Thomas E. Dewey. Truman won Montana by a large margin of 9.94%.

Results

United States presidential [1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Harry Truman (incumbent)	119,071	53.09%	4
	Republican	Thomas E. Dewey	96,770	43.15%	0
	Progressive	Henry Wallace	7,313	3.26%	0
	Socialist	Norman Thomas	695	0.31%	0
	Prohibition	Claude Watson	429	0.19%	0

References

1. http://uselectionatlas.org/RESULTS/index.html