United States House of Representatives elections in Indiana, 1996
Elections in Indiana |
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The 1996 congressional elections in Indiana were elections for Indiana's delegation to the United States House of Representatives, which occurred along with congressional elections nationwide on November 5, 1996. Republicans held a majority of Indiana's delegation over the Democrats, 6-4. Representatives were elected using the U.S. congressional districts based on the 1990 U.S. Census.
Results
The following are the final results from the Secretary of State of Indiana.[1]
Overview
United States House of Representatives elections in Indiana, 1996[2] | |||||
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Party | Votes | Percentage | Seats | +/– | |
Republican | 1,109,066 | 52.84% | 6 | - | |
Democratic | 930,919 | 44.34% | 4 | - | |
Libertarian | 59,085 | 2.81% | 0 | - | |
Others | 7 | <0.01% | 0 | - | |
Totals | 2,099,077 | 100.00% | 10 | - | |
See also
References
- ↑ "United States Representative". Indiana of Secretary of State. Retrieved 2008-11-09.
- ↑ http://clerk.house.gov/member_info/electioninfo/index.aspx
Preceded by 1994 elections |
United States House elections in Indiana 1996 |
Succeeded by 1998 elections |
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