United States presidential election in Wisconsin, 1996

United States presidential election in Wisconsin, 1996

November 5, 1996

Nominee Bill Clinton Bob Dole Ross Perot Party Democratic Republican Reform Home state Arkansas Kansas Texas Running mate Al Gore Jack Kemp Patrick Choate Electoral vote 11 0 0 Popular vote 1,071,971 845,029 227,339 Percentage 48.81% 38.48% 10.35%

County Results   Clinton—80-90%   Clinton—60-70%   Clinton—50-60%   Dole—40-50%   Dole—50-60%

President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

The 1996 United States presidential election in Wisconsin took place on November 5, 1996 as part of the 1996 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.

Wisconsin was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 48.81% to 38.48% by a margin of 10.33%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 10.35% of the popular vote.^[1]

Results

United States presidential election in Wisconsin, 1996
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Democratic	William Jefferson Clinton (Incumbent)	Albert Arnold Gore Jr. (Incumbent)	1,071,971	48.81%	11
	Republican	Robert Joseph Dole	Jack French Kemp	845,029	38.48%	0
	Reform	Henry Ross Perot	Patrick Choate	227,339	10.35%	0
	Independent	Ralph Nader	Winona LaDuke	28,723	1.31%	0
	U.S. Taxpayers' Party	Howard Phillips	Herbert Titus	8,811	0.40%	0
	Libertarian	Harry Browne	Jo Jorgensen	7,929	0.36%	0
	No party	Write-in		2,324	0.11%	0
	Independent	Dr. John Hagelin	Dr. V. Tompkins	1,379	0.06%	0
	Independent	Monica Moorehead	Gloria La Riva	1,333	0.06%	0
	Independent	Mary Cal Hollis	Eric Chester	848	0.04%	0
	Independent	James Harris	Laura Garza	483	0.02%	0

References

1. Dave Leip's Atlas of United States Presidential Election Results - 1996 Wisconsin Results

See also