United States presidential election in Washington (state), 1996

United States presidential election in Washington, 1996

November 5, 1996

Nominee Bill Clinton Bob Dole Ross Perot Party Democratic Republican Reform Home state Arkansas Kansas Texas Running mate Al Gore Jack Kemp Patrick Choate Electoral vote 11 0 0 Popular vote 1,123,323 840,712 201,003 Percentage 49.8% 37.3% 8.9%

County Results   Clinton—50-60%   Clinton—40-50%   Dole—40-50%   Dole—50-60%

President before election Bill Clinton Democratic Elected President Bill Clinton Democratic

The 1996 United States presidential election in Washington took place on November 5, 1996 as part of the 1996 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.

Washington was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 49.84% to 37.30% by a margin of 12.54%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 8.92% of the popular vote .^[1]

Results

United States presidential election in Washington, 1996
Party		Candidate	Running mate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton (incumbent)	Al Gore	1,123,323	49.84%	11
	Republican	Bob Dole	Jack Kemp	840,712	37.30%	0
	Reform	Ross Perot	Patrick Choate	201,003	8.92%	0
	Green Party	Ralph Nader	Winona LaDuke	60,322	2.68%	0
	Libertarian	Harry Browne	Jo Jorgensen	12,522	0.56%	0
	Natural Law	Dr. John Hagelin	Dr. V. Tompkins	6,076	0.27%	0
	U.S. Taxpayers'	Howard Phillips	Herbert Titus	4,578	0.20%	0
	Independent	Charles Collins	Rosemary Giumarra	2,374	0.11%	0
	Workers World Party	Monica Moorehead	Gloria La Riva	2,189	0.10%	0
	Socialist Workers Party	James Harris	Laura Garza	738	0.03%	0
Totals				2,253,837	100.0%	11

References

1. http://uselectionatlas.org/RESULTS/index.html

See also