United States presidential election in Arkansas, 1844
Main article: United States presidential election, 1844
| Elections in Arkansas | |||||||||
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The 1844 United States presidential election in Arkansas took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
Arkansas voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Arkansas by a margin of 26.02%.
Results
| United States presidential election in Arkansas, 1844[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 9,546 | 63.01% | 3 | 100.00% | ||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 5,604 | 36.99% | 0 | 0.00% | ||
| Total | 15,150 | 100.00% | 3 | 100.00% | ||||
References
- ↑ "1844 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved 23 December 2013.
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