United States presidential election in Delaware, 1844
Main article: United States presidential election, 1844
| Elections in Delaware | ||||||||||
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The 1844 United States presidential election in Delaware took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
Delaware voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Delaware by a margin of 2.45%.
Results
| United States presidential election in Delaware, 1844[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 6,271 | 51.20% | 3 | 100.00% | ||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 5,970 | 48.75% | 0 | 0.00% | ||
| N/A | Others | Others | 6 | 0.05% | 0 | 0.00% | ||
| Total | 12,247 | 100.00% | 3 | 100.00% | ||||
References
- ↑ "1844 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 23 December 2013.
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