United States presidential election in Maryland, 1836
Main article: United States presidential election, 1836
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The 1836 United States presidential election in Maryland took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.
Maryland voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Maryland by a margin of 7.46%.
Results
United States presidential election in Maryland, 1836[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Whig | William Henry Harrison | 25,852 | 53.73% | 10 | |
Democratic | Martin Van Buren | 22,267 | 46.27% | 0 | |
Totals | 48,119 | 100.0% | 10 | ||
References
- ↑ "1836 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 4 August 2012.
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