United States presidential election in Ohio, 1836

The 1836 United States presidential election in Ohio took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose twenty-one representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Ohio by a margin of 4.31%.

Results

United States presidential election in Ohio, 1836[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Whig	William Henry Harrison of Ohio	Francis Granger of New York	104,958	51.87%	21	100.00%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	96,238	47.56%	0	0.00%
	N/A	Others	Others	1,137	0.56%	0	0.00%
Total				202,333	100.00%	21	100.00%

References

1. "1836 Presidential General Election Results - Ohio". U.S. Election Atlas. Retrieved 23 December 2013.