United States Senate election in Ohio, 1988

November 8, 1988



Nominee	Howard Metzenbaum	George Voinovich
Party	Democratic	Republican
Popular vote	2,480,038	1,872,716
Percentage	56.97%	43.02%

County Results

U.S. Senator before election

Howard Metzenbaum
Democratic

Elected U.S. Senator

Howard Metzenbaum
Democratic

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The 1988 United States Senate election in Ohio was held on November 8, 1988. Incumbent Democratic U.S. Senator Howard Metzenbaum won re-election.^[1]

Major candidates

Democratic

Howard Metzenbaum, incumbent U.S. Senator

Republican

George Voinovich, Mayor of Cleveland and former Lieutenant Governor of Ohio.

Results

Ohio United States Senate election, 1988
Party		Candidate	Votes	%	±%
	Democratic	Howard Metzenbaum	2,480,038	56.97
	Republican	George Voinovich	1,872,716	42.31
	Independent	David Marshall	151	0.00
Majority			607,322	8.68
Turnout			4,352,905

References

↑ http://www.ourcampaigns.com/RaceDetail.html?RaceID=3542

(1986 ←) United States elections, 1988 (→ 1990)

President	United States presidential election, 1988

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