United States elections, 1990

**Partisan control of Congress and the presidency**
	Previous party	Incoming party
President	Republican	Republican
House	Democratic	Democratic
Senate	Democratic	Democratic

The 1990 United States midterm elections were held on November 6, and elected the members of the 102nd United States Congress. The election occurred in the middle of Republican President George H.W. Bush's lone term in office. The Democratic Party build on its majorities in both chambers of Congress. Bush's Republicans lost nine seats in the U.S. House, lower than the average number of seats lost by U.S. Presidents at the time, which was 29.^[1] Out of the 33 seats up for election in the Senate, the Democratic Party picked up a net gain of one seat.^[2] In the gubernatorial elections, both parties lost a net of one seat to third parties.

References

↑ "1990 Midterm Elections". Los Angeles Times. Retrieved 8 October 2011.
↑ "1990 Senatorial General Election Results". Uselectionatlas.org. Retrieved 8 October 2011.

United States elections

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See also Presidential elections Senate elections House elections Gubernatorial elections

(1988 ←) 1990 United States elections (→ 1992)

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United States elections, 1990

See also

References