United States presidential election in New Jersey, 1824

United States presidential election in New Jersey, 1824

October 26 – December 2, 1824

Nominee Andrew Jackson John Quincy Adams William H. Crawford Party Democratic-Republican Democratic-Republican Democratic-Republican Home state Tennessee Massachusetts Georgia Running mate John C. Calhoun John C. Calhoun Nathaniel Macon Electoral vote 8 0 0 Popular vote 10,332 8,309 1,196 Percentage 52.08% 41.89% 6.03%

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

The 1824 United States presidential election in New Jersey took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. New Jersey voted for Andrew Jackson over John Quincy Adams, William H. Crawford, and Henry Clay. Jackson won New Jersey by a margin of 10.19%.

Results

United States presidential election in New Jersey, 1824[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	Andrew Jackson	10,332	'52.08%	8
	Democratic-Republican	John Quincy Adams	8,309	41.89%	0
	Democratic-Republican	William H. Crawford	1,196	6.03%	0
Totals			19,837	100.0%	8

References

1. "1824 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved 27 February 2013.