United States presidential election in Kentucky, 1824

United States presidential election in Kentucky, 1824

October 26 – December 2, 1824

Nominee Henry Clay Andrew Jackson Party Democratic-Republican Democratic-Republican Home state Kentucky Tennessee Running mate Nathan Sanford John C. Calhoun Electoral vote 14 0 Popular vote 16,982 6,356 Percentage 72.77% 27.23%

The 1824 United States presidential election in Kentucky took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Kentucky voted for Henry Clay over Andrew Jackson, John Quincy Adams, and William H. Crawford. Clay won Kentucky, his home state, by a wide margin of 45.54%.

Results

United States presidential election in Kentucky, 1824[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	Henry Clay	16,982	72.77%	14
	Democratic-Republican	Andrew Jackson	6,356	27.23%	0
Totals			23,338	100.0%	14

References

1. "1824 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved 27 February 2013.