Vermont gubernatorial election, 1912
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The Vermont gubernatorial election of 1912 took place on September 3, 1912. Incumbent Republican John A. Mead, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Allen M. Fletcher defeated Democratic candidate Harland B. Howe and Progressive candidate Frazer Metzger to succeed him. Since no candidate won a majority of the popular vote, the election was decided and Fletcher was elected by the Vermont General Assembly in accordance with the state constitution.[2]
Results
Vermont gubernatorial election, 1912[2] | |||||
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Party | Candidate | Votes | % | ±% | |
Republican | Allen M. Fletcher | 26,237 | 40.5 | ||
Democratic | Harland B. Howe | 20,001 | 30.8 | ||
Progressive | Frazer Metzger | 15,629 | 24.1 | ||
Prohibition | Clement F. Smith | 1,735 | 2.7 | ||
Socialist | Fred W. Suitor | 1,210 | 1.9 | ||
N/A | Other | 27 | 0.0 | ||
Total votes | 64,839 | 100 | |||
References
- ↑ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 1 January 2015.
- 1 2 "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 1 January 2015.
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