United States Senate elections, 1890
United States Senate elections, 1890
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Majority Party before election
Republicans
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Elected Majority Party
Republican
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The United States Senate election of 1890 was an election in which the Republican Party lost four seats in the United States Senate, though still retaining a commanding majority.
As this election was prior to ratification of the seventeenth amendment, Senators were chosen by State legislatures.
Results
52nd Congress (1891–1893)
- Majority Party: Republican (47)
- Minority Party: Democratic (39)
- Other Parties: Populist (2)
- Total Seats: 88
Change in Senate composition
Senate composition in the 51st Congress |
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Senate composition in the 52nd Congress |
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List of races
Idaho
In July 1890, Idaho became a state. In November, Fred Dubois helped engineer a plan for the Idaho Legislature to effectively elect three people to the U.S. Senate: Governor George Shoup to the Class 2 seat up for election in 1894, state constitutional convention member William J. McConnell to serve for the remainder of the Fifty-first United States Congress, ending in March 1891, and Dubois himself to succeed McConnell and serve a full six-year term in the Class 3 seat beginning in March 1891.
See also
References