United States presidential election in Delaware, 1840

The 1840 United States presidential election in Delaware took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Delaware by a margin of 10.1%.

Results

United States presidential election in Delaware, 1840[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Whig	William Henry Harrison of Ohio	John Tyler of Virginia	5,967	54.99%	3	100.00%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	4,872	44.89%	0	0.00%
	N/A	Others	Others	13	0.12%	0	0.00%
Total				10,852	100.00%	3	100.00%

References

1. "1840 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 23 December 2013.