United States presidential election in Alabama, 1840

The 1840 United States presidential election in Alabama took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

Alabama voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Alabama by a margin of 8.76%.

Results

United States presidential election in Alabama, 1840[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	33,996	54.38%	7	100.00%
	Whig	William Henry Harrison of Ohio	John Tyler of Virginia	28,515	45.62%	0	0.00%
Total				62,511	100.00%	7	100.00%

References

1. "1840 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved 23 December 2013.